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What would happen to the rate of a reaction with rate law rate = k [NO]2[H2] if the concentration of NO were doubled?A.The rate would be four times larger.B.The rate would be halved.C.The rate would not change.D.The rate would also be doubled.

Question

What would happen to the rate of a reaction with rate law rate = k [NO]2[H2] if the concentration of NO were doubled?A.The rate would be four times larger.B.The rate would be halved.C.The rate would not change.D.The rate would also be doubled.

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Solution

The rate law for the reaction is given as rate = k [NO]²[H2]. This means that the rate of the reaction is directly proportional to the square of the concentration of NO and directly proportional to the concentration of H2.

If the concentration of NO is doubled, then the new rate would be k (2[NO])²[H2] = 4k [NO]²[H2].

So, the rate of the reaction would be four times larger if the concentration of NO is doubled. Therefore, the correct answer is A. The rate would be four times larger.

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