The peak current in a resistor is given by Ohm's law, which states that the current I through a conductor between two points is directly proportional to the voltage V across the two points, and inversely proportional to the resistance R between them. This is usually written as:

I = V / R

In this case, we're told that the peak current I is 1.50 A when the resistance R is a certain value. If the resistance is tripled, the new resistance is 3R. Substituting this into Ohm's law gives:

I' = V / 3R

Since V is constant (the emf is oscillating but we're only interested in the peak values), we can see that the new current I' is one third of the original current I. Therefore, the peak current when the resistance is tripled is 1.50 A / 3 = 0.500 A.

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The peak current in a resistor is given by Ohm's law, which states that the current I through a conductor between two points is directly proportional to the voltage V across the two points, and inversely proportional to the resistance R between them. This is usually written as:

I = V / R

In this case, we're told that the peak current I is 1.50 A when the resistance R is a certain value. If the resistance is tripled, the new resistance is 3R. Substituting this into Ohm's law gives:

I' = V / 3R

Since V is constant (the emf is oscillating but we're only interested in the peak values), we can see that the new current I' is one third of the original current I. Therefore, the peak current when the resistance is tripled is 1.50 A / 3 = 0.500 A.

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The peak current in a resistor is given by Ohm's law, which states that the current I through a conductor between two points is directly proportional to the voltage V across the two points, and inversely proportional to the resistance R between them. This is usually written as:

I = V / R

In this case, we're told that the peak current I is 1.50 A when the resistance R is a certain value. If the resistance is tripled, the new resistance is 3R. Substituting this into Ohm's law gives:

I' = V / 3R

Since V is constant (the emf is oscillating but we're only interested in the peak values), we can see that the new current I' is one third of the original current I. Therefore, the peak current when the resistance is tripled is 1.50 A / 3 = 0.500 A.

A resistor is connected across an oscillating emf with a peak current through the resistor of 1.50 A. If the resistance R is tripled, what is the peak current? 0.500 A 0.866 A 1.50 A 4.50 A

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