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Question:-The cost of registration at a professional association meeting was $50 per person; a lunch for registrants only was available for an additional $22 per person. If the number of registrants who paid for lunch was 100 more than the number who did not, and if receipts for registration and lunch totaled $92,600, how many people paid just for registration at the meeting?Choices:- 700 800 1300 1500

Question

Question:-The cost of registration at a professional association meeting was 50perperson;alunchforregistrantsonlywasavailableforanadditional50 per person; a lunch for registrants only was available for an additional 22 per person. If the number of registrants who paid for lunch was 100 more than the number who did not, and if receipts for registration and lunch totaled $92,600, how many people paid just for registration at the meeting?Choices:- 700 800 1300 1500

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Solution

Let's denote the number of people who paid just for registration as x. Then the number of people who paid for both registration and lunch is x + 100.

The total cost for registration is $50 per person, so the total cost for those who paid just for registration is 50x.

The total cost for registration and lunch is 50+50 + 22 = $72 per person, so the total cost for those who paid for both is 72(x + 100).

The total receipts for registration and lunch is given as $92,600. Therefore, we can set up the following equation:

50x + 72(x + 100) = 92600

Solving this equation will give us the value of x, which is the number of people who paid just for registration.

First, distribute the 72:

50x + 72x + 7200 = 92600

Then, combine like terms:

122x + 7200 = 92600

Subtract 7200 from both sides:

122x = 85400

Finally, divide by 122:

x = 700

So, 700 people paid just for registration at the meeting.

This problem has been solved

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