Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.You may assume that each input would have exactly one solution, and you may not use the same element twice.You can return the answer in any order.

Here is a Python solution for the problem:

def twoSum(nums, target):
    h = {}
    for i, num in enumerate(nums):
        n = target - num
        if n not in h:
            h[num] = i
        else:
            return [h[n], i]

This function works

Sure, here is a Python solution using a dictionary to store the numbers and their indices.

def twoSum(nums, target):
    num_dict = {}
    for i, num in enumerate(nums):
        if target - num in num_dict:
            return [num_dict[target - num], i]
        num_dict[num] = i

This function works as follows:

1. It first creates an empty dictionary num_dict.
2. Then it iterates over the list nums using enumerate to get both the index i and the number num.
3. In each iteration, it checks if target - num is in the dictionary. If it is, it means we have found two numbers which add up to the target, so it returns a list with the indices of these

To solve this problem, we can use a two-pointer approach.

First, we will create a dictionary to store the values and their corresponding indices from the input array.

Then, we will iterate through the array and for each element, we will check if the difference between the target and the current element exists in the dictionary. If it does, we have found the pair of numbers that add up to the target.

Finally, we will return the indices of the two numbers.

Here is a Python solution for the problem:

def twoSum(nums, target):
    h = {}
    for i, num in enumerate(nums):
        n = target - num
        if n not in h:
            h[num] = i
        else:
            return [h[n], i]

This function works by iterating over the list of numbers. For each number, it calculates the difference between the target and the current number. If this difference is not in the dictionary h, it adds the current number and its index to h. If the difference is in h, it means we have found two numbers that add up to the target, so it returns their indices.

To solve this problem, we can use a two-pointer approach.

First, we will create a dictionary to store the values and their corresponding indices from the input array.

Then, we will iterate through the array and for each element, we will check if the difference between the target and the current element exists in the dictionary. If it does, we have found the pair of numbers that add up to the target.

Finally, we will return the indices of the two numbers.