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A tennis ball is traveling at 20 m/s west and 5 m/s up. What is the overall magnitude of the tennis ball's velocity vector?25 m/s20.6 m/s425 m/s 5 m/s20 m/s

Question

A tennis ball is traveling at 20 m/s west and 5 m/s up. What is the overall magnitude of the tennis ball's velocity vector?25 m/s20.6 m/s425 m/s 5 m/s20 m/s

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Solution

The magnitude of the velocity vector can be found using the Pythagorean theorem, since the two components of the velocity (20 m/s west and 5 m/s up) are perpendicular to each other.

The Pythagorean theorem is a^2 + b^2 = c^2, where a and b are the two perpendicular components and c is the hypotenuse (in this case, the magnitude of the velocity vector).

So, we substitute the given values into the formula:

(20 m/s)^2 + (5 m/s)^2 = c^2 400 m^2/s^2 + 25 m^2/s^2 = c^2 425 m^2/s^2 = c^2

Taking the square root of both sides to solve for c gives:

c = sqrt(425 m^2/s^2) c = 20.6 m/s

So, the magnitude of the tennis ball's velocity vector is 20.6 m/s.

This problem has been solved

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