A ball is projected straight up with an initial velocity of 20 m/s. After 0.3 seconds its velocity will be Question 7Answera.0 m/sb.-20 m/sc.22.94 m/sd.20 m/se.17.06 m/s
Question
A ball is projected straight up with an initial velocity of 20 m/s. After 0.3 seconds its velocity will be Question 7Answera.0 m/sb.-20 m/sc.22.94 m/sd.20 m/se.17.06 m/s
Solution
The velocity of an object under the influence of gravity can be calculated using the formula:
v = u - gt
where: v is the final velocity, u is the initial velocity, g is the acceleration due to gravity (approximately 9.8 m/s² on Earth), and t is the time.
In this case, the ball is projected straight up with an initial velocity (u) of 20 m/s. After 0.3 seconds (t), we want to know its velocity (v). The acceleration due to gravity (g) is 9.8 m/s².
Substituting these values into the formula gives:
v = 20 - 9.8 * 0.3 v = 20 - 2.94 v = 17.06 m/s
So, the velocity of the ball after 0.3 seconds will be 17.06 m/s. Therefore, the answer is e. 17.06 m/s.
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