Calculate the energy required to heat 0.90kg of ammonia from 42.0°C to 61.2°C. Assume the specific heat capacity of ammonia under these conditions is ·4.70J·g−1K−1 . Be sure your answer has the correct number of significant digits.
Question
Calculate the energy required to heat 0.90kg of ammonia from 42.0°C to 61.2°C. Assume the specific heat capacity of ammonia under these conditions is ·4.70J·g−1K−1 . Be sure your answer has the correct number of significant digits.
Solution
To calculate the energy required to heat a substance, we can use the formula:
q = mcΔT
where: q = heat energy m = mass c = specific heat capacity ΔT = change in temperature
Given: m = 0.90 kg = 900 g (since 1 kg = 1000 g) c = 4.70 J/g·K ΔT = 61.2°C - 42.0°C = 19.2 K (since a change of 1°C is equal to a change of 1 K)
Substituting the given values into the formula:
q = (900 g) * (4.70 J/g·K) * (19.2 K) = 81072 J
So, the energy required to heat 0.90 kg of ammonia from 42.0°C to 61.2°C is 81072 J. However, considering significant figures, we should round this to three significant figures as the least number of significant figures among the given numbers is three (in 0.90 kg and 4.70 J/g·K).
Therefore, the energy required is approximately 81100 J.
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