Calculate the energy required to heat 0.60kg of mercury from −1.3°C to 11.9°C. Assume the specific heat capacity of mercury under these conditions is ·0.139J·g−1K−1 . Round your answer to 2 significant digits.
Question
Calculate the energy required to heat 0.60kg of mercury from −1.3°C to 11.9°C. Assume the specific heat capacity of mercury under these conditions is ·0.139J·g−1K−1 . Round your answer to 2 significant digits.
Solution
To calculate the energy required to heat a substance, we can use the formula:
Q = mcΔT
where: Q = heat energy m = mass c = specific heat capacity ΔT = change in temperature
Given: m = 0.60 kg = 600 g (since 1 kg = 1000 g) c = 0.139 J/g·K ΔT = 11.9°C - (-1.3°C) = 13.2 K (since degrees Celsius and Kelvin have the same scale)
Substituting these values into the formula, we get:
Q = (600 g) * (0.139 J/g·K) * (13.2 K) = 1101.36 J
Rounding to two significant digits, the energy required to heat 0.60 kg of mercury from -1.3°C to 11.9°C is approximately 1100 J.
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