Calculate the amount of heat required to raise the temperature of 967.2 mL of a solution from 25.1 °C to 35.7 °C if the solution has a density of 1.04 g mL–1 and a heat capacity of 4.08 J K–1 g–1.Question 1Answer43.5 kJ41.8 kJ40.2 kJ2.61 kJ
Question
Calculate the amount of heat required to raise the temperature of 967.2 mL of a solution from 25.1 °C to 35.7 °C if the solution has a density of 1.04 g mL–1 and a heat capacity of 4.08 J K–1 g–1.Question 1Answer43.5 kJ41.8 kJ40.2 kJ2.61 kJ
Solution
To calculate the amount of heat required, we can use the formula:
q = mcΔT
where:
- q is the heat energy
- m is the mass of the substance
- c is the specific heat capacity
- ΔT is the change in temperature
First, we need to calculate the mass of the solution. We can do this by multiplying the volume of the solution by its density:
m = 967.2 mL * 1.04 g/mL = 1005.888 g
Next, we calculate the change in temperature:
ΔT = 35.7°C - 25.1°C = 10.6°C Note: Since we're dealing with a change in temperature, it doesn't matter whether we use Celsius or Kelvin because the difference is the same.
Now we can substitute these values into the formula:
q = (1005.888 g) * (4.08 J/g°C) * (10.6°C) = 43459.6 J
Since 1 kJ = 1000 J, we convert J to kJ:
q = 43459.6 J * (1 kJ / 1000 J) = 43.5 kJ
So, the amount of heat required is 43.5 kJ.
Similar Questions
Calculate the amount of heat required to raise the temperature of 851.2 mL of a solution from 22.9 °C to 35.2 °C if the solution has a density of 1.04 g mL–1 and a heat capacity of 4.08 J K–1 g–1.
A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system is 37.1°C, what is the specific heat capacity of the substance? Use 4.184 J / g °C for the specific heat capacity of water. A. 368 J / g °C B. 13.1 J / g °C C. 0.368 J / g °C D. 0.0112 J / g °C
The specific heat capacity of water is 4.184 J g -1 K -1 . Calculate the amount of heatrequired to raise the temperature of 1.00 g of water by 1.00 K
How much heat is required to raise the temperature of 1500 g of water from 25 °C to52 °C?Question 2Select one:a.1500 kJb.169 kJc.6.27 kJd.40.5 Je.40.5 kJ
The energy needed to increase the temperature of 1.2 kg of oil by 40 °C was 100.8 kJ.Calculate the specific heat capacity of this oil._________ J/kg°CYou do not need to give units in your answer.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.