Find the sum of all two digits numbers divisible by 6

Step 1: Identify the two-digit numbers divisible by 6. The smallest two-digit number divisible by 6 is 12 and the largest is 96.

Step 2: Find the sum of the smallest and largest number. Sum = 12 + 96 = 108

Step 3: Identify the total number of two-digit numbers divisible by 6. This can be done by dividing the difference of the largest and smallest number by 6 and then adding 1. Total numbers = (96 - 12)/6 + 1 = 15

Step 4: Use the formula for the sum of an arithmetic series to find the sum of all two-digit numbers divisible by 6. The formula is Sum = n/2 * (a + l) where n is the total number of terms, a is the first term and l is the last term.

Step 5: Substitute the values into the formula. Sum = 15/2 * (12 + 96) = 7.5 * 108 = 810

So, the sum of all two-digit numbers divisible by 6 is 810.