The sum of 2 consecutive multiples of 6 and 66 , Find the multiples?

The question is asking for two consecutive multiples of 6 that, when added together, equal 66.

Step 1: Let's denote the first multiple of 6 as 6n. Because we're looking for consecutive multiples, the next multiple of 6 would be 6n + 6.

Step 2: According to the problem, these two multiples add up to 66. So, we can set up the following equation: 6n + 6n + 6 = 66.

Step 3: Simplify the equation to 12n + 6 = 66.

Step 4: Subtract 6 from both sides of the equation to isolate the term with n: 12n = 60.

Step 5: Divide both sides of the equation by 12 to solve for n: n = 5.

So, the two consecutive multiples of 6 that add up to 66 are 65 = 30 and 6(5+1) = 36.