What is the output of the following code:void main(){int i;for(i=65;i<70;i++) printf(“%c,”,i);}a.65,66,67,68,69,70b.a,b,c,d,e,c.A,B,C,D,E,d.A,B,C,D,E
Question
What is the output of the following code:void main(){int i;for(i=65;i<70;i++) printf(“%c,”,i);}a.65,66,67,68,69,70b.a,b,c,d,e,c.A,B,C,D,E,d.A,B,C,D,E
Solution
To determine the output of the given code, let's analyze it step by step:
- The code starts with the declaration of the main function:
void main(). - Inside the main function, there is a for loop that initializes the variable
iwith the value 65:for(i=65;i<70;i++). - The loop will continue as long as
iis less than 70. - In each iteration of the loop, the code will execute the
printffunction, which will print the value ofias a character followed by a comma:printf("%c,",i). - The value of
iwill be incremented by 1 after each iteration. - The loop will continue until
ireaches 70, at which point the conditioni<70will evaluate to false and the loop will terminate. - The output of the code will be the characters corresponding to the ASCII values 65, 66, 67, 68, and 69, separated by commas.
Therefore, the correct answer is: a. 65, 66, 67, 68, 69
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