he correct answerWhat will be the error in the following Java code? byte ct = 67; ct = ct * 67;Optionsct cannot contain value 100, limited by its rangect cannot contain value 67* operator has converted ct * 67 into int, which can not be converted to byte without castingNo error in this code
Question
he correct answerWhat will be the error in the following Java code? byte ct = 67; ct = ct * 67;Optionsct cannot contain value 100, limited by its rangect cannot contain value 67* operator has converted ct * 67 into int, which can not be converted to byte without castingNo error in this code
Solution
The error in the given Java code is that the "* operator has converted ct * 67 into int, which can not be converted to byte without casting".
Here's why:
In Java, when you perform arithmetic operations (like multiplication) on byte or short integer types, they are first promoted to int before the operation is carried out. This is called type promotion.
So, in the given code, when you do "ct * 67", the byte value 'ct' is promoted to int, the multiplication is performed, and the result is also an int.
Now, when you try to assign this int result back to the byte variable 'ct', it causes a compile-time error because a byte can only hold values from -128 to 127, and an explicit type casting is required to convert int to byte.
So, to correct the code, you should cast the result of the multiplication to byte, like this:
ct = (byte) (ct * 67);
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