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Sushant is given an array of integers representing a sequence. He wants to implement a program to transform the array according to the following rules: Replace the first element with the sum of itself and the second element.Replace other elements with the sum of the previous and the next elements.Replace the last element with the sum of itself and the previous element.Help him write the code to output the modified array using malloc().For Example,If the array elements are 10, 20, 30, 40, 50; the calculations are as follows:First element = 10+20 = 30Second element = 10+30 = 40Third element = 20+40 = 60Fourth element = 30+50 = 80Last element = 40+50 = 90Therefore, the final array is 30, 40, 60, 80, 90.

Question

Sushant is given an array of integers representing a sequence. He wants to implement a program to transform the array according to the following rules: Replace the first element with the sum of itself and the second element.Replace other elements with the sum of the previous and the next elements.Replace the last element with the sum of itself and the previous element.Help him write the code to output the modified array using malloc().For Example,If the array elements are 10, 20, 30, 40, 50; the calculations are as follows:First element = 10+20 = 30Second element = 10+30 = 40Third element = 20+40 = 60Fourth element = 30+50 = 80Last element = 40+50 = 90Therefore, the final array is 30, 40, 60, 80, 90.

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Solution

Here is a C program that implements the transformation you described:

#include <stdio.h>
#include <stdlib.h>

void transformArray(int* arr, int n) {
    int* newArr = (int*)malloc(n * sizeof(int));

    newArr[0] = arr[0] + arr[1];
    newArr[n-1] = arr[n-1] + arr[n-2];

    for(int i = 1; i < n-1; i++) {
        newArr[i] = arr[i-1] + arr[i+1];
    }

    for(int i = 0; i < n; i++) {
        printf("%d ", newArr[i]);
    }

    free(newArr);
}

int main() {
    int arr[] = {10, 20, 30, 40, 50};
    int n = sizeof(arr)/sizeof(arr[0]);

    transformArray(arr, n);

    return 0;
}

This program first allocates memory for a new array using malloc(). It then calculates the new values for the first and last elements of the array. After that, it loops through the rest of the array, calculating the new values for each element. Finally, it prints the new array and frees the memory that was allocated for it.

This problem has been solved

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