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Find the Maclaurin polynomial p1(x) for f(x)=18x+8.

Question

Find the Maclaurin polynomial p1(x) for f(x)=18x+8.

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Solution

The Maclaurin series is a Taylor series expansion of a function about 0.

For a function f(x) = 18x + 8, it's already a polynomial of degree 1. So, its Maclaurin polynomial p1(x) is the same as the function itself.

Therefore, p1(x) = 18x + 8.

Similar Questions

Find the Maclaurin polynomial p3(x) for f(x)=5x .

Find the first and second degree Maclaurin polynomials for the function  f(x)=5ex+3e−x centered at  a=0 .Select the correct answer below:T1(x)=8+3x,T2(x)=8+3x+4x2 T1(x)=8+2x,T2(x)=8+2x+4x2 T1(x)=8+2x,T2(x)=8+2x−4x2 T1(x)=8−2x,T2(x)=8−2x+4x2

Now find the function values.f(0)  =  18 f 𝜋6 =  0 f 𝜋2

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Find the Taylor polynomial p2(x) for f(x)=5ex at x=1 .

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