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For the reaction A → B, ΔH = -13 kJ mol-1 and Ea = 31 kJ mol-1 . What is theactivation energy for the reverse reaction B → A?

Question

For the reaction A → B, ΔH = -13 kJ mol-1 and Ea = 31 kJ mol-1 . What is theactivation energy for the reverse reaction B → A?

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Solution

The activation energy for the reverse reaction B → A can be calculated using the formula:

Ea(reverse) = ΔH + Ea(forward)

Where: Ea(reverse) is the activation energy for the reverse reaction, ΔH is the change in enthalpy for the forward reaction, and Ea(forward) is the activation energy for the forward reaction.

Given that ΔH = -13 kJ mol-1 and Ea(forward) = 31 kJ mol-1, we can substitute these values into the formula:

Ea(reverse) = -13 kJ mol-1 + 31 kJ mol-1 = 18 kJ mol-1

So, the activation energy for the reverse reaction B → A is 18 kJ mol-1.

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