What does the following Python code snippet accomplish?def reverse_linked_list(head): prev = None current = head while current is not None: next_node = current.next current.next = prev prev = current current = next_node head = prev return headDeletes the last node of the linked listInserts a new node at the beginning of the linked listReverses the linked listSorts the linked list in ascending order
Question
What does the following Python code snippet accomplish?def reverse_linked_list(head): prev = None current = head while current is not None: next_node = current.next current.next = prev prev = current current = next_node head = prev return headDeletes the last node of the linked listInserts a new node at the beginning of the linked listReverses the linked listSorts the linked list in ascending order
Solution
The provided Python code snippet accomplishes the task of reversing a linked list.
Similar Questions
f reverse_linked_list(head): prev = None current = head while current is not None: next_node = current.next current.next = prev prev = current current = next_node head = prev return headDeletes the last node of the linked listInserts a new node at the beginning of the linked listReverses the linked listSorts the linked list in ascending order
What does the following Python code snippet accomplish?class LinkedList: def __init__(self): self.head = None def insert_at_beginning(self, data): new_node = Node(data) new_node.next = self.head self.head = new_nodeInserts a new node at the beginning of the linked listDeletes the last node of the linked listAppends a new node to the end of the linked listReverses the linked list
What is the output of the following Python code snippet?class LinkedList: def __init__(self): self.head = None def append(self, data): new_node = Node(data) if self.head is None: self.head = new_node else: current = self.head while current.next: current = current.next current.next = new_node def display(self): current = self.head while current: print(current.data, end=" ") current = current.nextll = LinkedList()ll.append(1)ll.append(2)ll.display()
he following function reverse() is supposed to reverse a singly linked list. There is one line missing at the end of the function./* Link list node */struct node{ int data; struct node* next;}; /* head_ref is a double pointer which points to head (or start) pointer of linked list */static void reverse(struct node** head_ref){ struct node* prev = NULL; struct node* current = *head_ref; struct node* next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } /*ADD A STATEMENT HERE*/} What should be added in place of “/*ADD A STATEMENT HERE*/”, so that the function correctly reverses a linked list.
What does the following Python code snippet do?def delete_node(self, key): temp = self.head if temp is not None: if temp.data == key: self.head = temp.next temp = None return while temp is not None: if temp.data == key: break prev = temp temp = temp.next if temp == None: return prev.next = temp.next temp = None
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