Find the coordinates of the turning point on the graph of y=−3(x−3)(x−8
Question
Find the coordinates of the turning point on the graph of y=−3(x−3)(x−8
Solution
The turning point of a quadratic function is also known as the vertex. The vertex form of a quadratic function is y=a(x-h)^2+k, where (h,k) are the coordinates of the vertex.
In the given function y=-3(x-3)(x-8), we can find the x-coordinate of the vertex by finding the average of the roots of the equation. The roots are the values of x for which y=0, which are 3 and 8 in this case.
So, the x-coordinate of the vertex is (3+8)/2 = 5.5.
To find the y-coordinate of the vertex, we substitute x=5.5 into the equation:
y = -3(5.5-3)(5.5-8) = -3(2.5)(-2.5) = 18.75.
So, the coordinates of the turning point (vertex) are (5.5, 18.75).
Similar Questions
Find the coordinates of the turning point on the graph of y=3x 2 −2x−1
Instructions: Given the function, state the vertex.y=−3(x+4)2−8
At how many points does the graph of the function below intersect the x-axis?y = 3x2 - 8x + 8
Find the coordinates of the vertex of the graph of the following equation: 𝑦=(𝑥−3)(𝑥−7)y=(x−3)(x−7)
Which two points are on the graph of y = x - 3?(3, 0), (0, 3)(0, -3), (4, 1)(1, 2), (0, 3)(1, -2), (-1, 3)
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.