A sample of gas was heated 50 K initially and increased to 100 K within a given time. The volume is also increased from 2.0L to 3.0L. If the original pressure was 1.2 atm, what is the new pressure?*2 puntos1.2 atm1.5 atm1.3 atm1.6 atm
Question
A sample of gas was heated 50 K initially and increased to 100 K within a given time. The volume is also increased from 2.0L to 3.0L. If the original pressure was 1.2 atm, what is the new pressure?*2 puntos1.2 atm1.5 atm1.3 atm1.6 atm
Solution
To solve this problem, we can use the combined gas law which states that the ratio of the product of pressure and volume to temperature remains constant.
The combined gas law formula is: P1V1/T1 = P2V2/T2
Where: P1 = initial pressure = 1.2 atm V1 = initial volume = 2.0 L T1 = initial temperature = 50 K
P2 = final pressure (we are solving for this) V2 = final volume = 3.0 L T2 = final temperature = 100 K
Rearranging the formula to solve for P2 gives us: P2 = P1*V1/T1 * T2/V2
Substituting the given values into the formula gives us: P2 = 1.2 atm * 2.0 L / 50 K * 100 K / 3.0 L
Solving this gives us: P2 = 1.6 atm
So, the new pressure is 1.6 atm.
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