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What will be the output of the following Python code?x = 50def func(x): print('x is', x) x = 2 print('Changed local x to', x)func(x)print('x is now', x)x is 50Changed local x to 2x is now 100x is 50Changed local x to 2x is now 2None of the mentionedx is 50Changed local x to 2x is now 50

Question

What will be the output of the following Python code?x = 50def func(x): print('x is', x) x = 2 print('Changed local x to', x)func(x)print('x is now', x)x is 50Changed local x to 2x is now 100x is 50Changed local x to 2x is now 2None of the mentionedx is 50Changed local x to 2x is now 50

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Solution

The output of the given Python code will be:

x is 50 Changed local x to 2 x is now 50

This is because the function func(x) is given the value of x (which is 50), and within the function, x is changed to 2. However, this change is local to the function and does not affect the global variable x. Therefore, after the function is called, the print statement prints the global variable x, which is still 50.

This problem has been solved

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