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Write a C program to represent the following Boolean Expression, Where A, B, C & D are the Binary Inputs.Out = (A.B).(C+D)Print the value of Out for the following values of(a) A = 1; B = 1; C = 0; D = 1;(b) A = 1; B = 0; C = 1; D = 0;(c) A = 1; B = 1; C = 1; D = 1;(d) A = 0; B = 0; C = 1; D = 1;

Question

Write a C program to represent the following Boolean Expression, Where A, B, C & D are the Binary Inputs.Out = (A.B).(C+D)Print the value of Out for the following values of(a) A = 1; B = 1; C = 0; D = 1;(b) A = 1; B = 0; C = 1; D = 0;(c) A = 1; B = 1; C = 1; D = 1;(d) A = 0; B = 0; C = 1; D = 1;

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Solution

Here is a simple C program that represents the Boolean expression and prints the value of Out for the given values of A, B, C, and D.

#include <stdio.h>

int main() {
    int A, B, C, D;
    int Out;

    // (a) A = 1; B = 1; C = 0; D = 1;
    A = 1; B = 1; C = 0; D = 1;
    Out = (A && B) && (C || D);
    printf("Out for A = 1; B = 1; C = 0; D = 1; is %d\n", Out);

    // (b) A = 1; B = 0; C = 1; D = 0;
    A = 1; B = 0; C = 1; D = 0;
    Out = (A && B) && (C || D);
    printf("Out for A = 1; B = 0; C = 1; D = 0; is %d\n", Out);

    // (c) A = 1; B = 1; C = 1; D = 1;
    A = 1; B = 1; C = 1; D = 1;
    Out = (A && B) && (C || D);
    printf("Out for A = 1; B = 1; C = 1; D = 1; is %d\n", Out);

    // (d) A = 0; B = 0; C = 1; D = 1;
    A = 0; B = 0; C = 1; D = 1;
    Out = (A && B) && (C || D);
    printf("Out for A = 0; B = 0; C = 1; D = 1; is %d\n", Out);

    return 0;
}

This program first declares the variables A, B, C, D, and Out. Then it assigns the given values to A, B, C, and D, calculates the value of the Boolean expression using the logical AND (&&) and OR (||) operators, and assigns the result to Out. Finally, it prints the value of Out. This process is repeated for each set of values.

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