Which is a correct version of the Hardy-Weinberg equation for genotype frequencies in a population in equilibrium?Multiple choice question.p/q = 1p x 2pq x q = 1p2 + q2 = 1p2 + 2pq + q2 = 1

For a gene with two alleles whose frequencies are p and q, the Hardy-Weinberg equation states that the genotypes that are possible for the population are p2 + 2pq + q2, which is equal to Blank______.Multiple choice question.(p + q)2p2 - q2p2 + q2q - p

Which of the following is an accurate depiction of the Hardy-Weinberg equation for a gene with two alleles?Multiple choice question.p2 + q2 = 2pqp2 + 2pq + q2 = 1p2 + pq + q2 = 1

In the Hardy–Weinberg equilibrium, the terms p2, 2pq, and q2 refer toMultiple choice question.allele frequencies of a gene in a population.numbers of individuals in a population.genotype frequencies in a population.phenotype frequencies in a population.

Use the equation p2 + 2pq + q2 = 1.0 to solve the following problem. In a population of 100 squirrels there are 64 black ones, and the remaining are white. Black (B) is the dominant allele, and white (b) is the recessive allele. If the population is in Hardy-Weinberg equilibrium, what is the frequency of the black squirrels that are heterozygous (Bb) for their coat color?Multiple choice question.0.480.960.160.40

Match the term on the left with its meaning for Hardy-Weinberg equilibrium on the right.InstructionsDrag and drop application.p2p2 drop zone empty.2pq2pq drop zone empty.q2q2 drop zone empty.pp drop zone empty.qq drop zone empty.frequency of heterozygous genotypefrequency of homozygous dominant genotypefrequency of recessive allelefrequency of dominant allelefrequency of homozygous recessive genotype