Given the following atomic masses (C: 12.01 amu; H 1.01 amu; O 16.00 amu), the formula mass of C9H8O4 in amu to the correct number of significant figures is (only include numbers in the box):
Question
Given the following atomic masses (C: 12.01 amu; H 1.01 amu; O 16.00 amu), the formula mass of C9H8O4 in amu to the correct number of significant figures is (only include numbers in the box):
Solution
To calculate the formula mass of C9H8O4, we need to multiply the atomic mass of each element by the number of atoms of that element in the molecule, and then add all these values together.
- Carbon (C): 9 atoms * 12.01 amu/atom = 108.09 amu
- Hydrogen (H): 8 atoms * 1.01 amu/atom = 8.08 amu
- Oxygen (O): 4 atoms * 16.00 amu/atom = 64.00 amu
Now, add all these values together:
108.09 amu (C) + 8.08 amu (H) + 64.00 amu (O) = 180.17 amu
So, the formula mass of C9H8O4 is 180.17 amu.
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