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What is the result of the following script: x = 5y = 0try:z = x/yexcept ZeroDivisionError:z=0 #handlehereprint(z) #output as 0print(aTuple[-4:-1])        A0BZero Division Error OccurredCAnother error will occur, the program will "crash"D5

Question

What is the result of the following script: x = 5y = 0try:z = x/yexcept ZeroDivisionError:z=0 #handlehereprint(z) #output as 0print(aTuple[-4:-1])        A0BZero Division Error OccurredCAnother error will occur, the program will "crash"D5

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Solution

The script first sets x to 5 and y to 0. It then tries to divide x by y and assign the result to z. However, since division by zero is undefined, a ZeroDivisionError is raised. The script catches this error and sets z to 0.

Then it tries to print a variable called aTuple, which has not been defined in the script. This will raise a NameError, because the script tries to access a variable that does not exist.

So, the correct answer is C: Another error will occur, the program will "crash".

This problem has been solved

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