If two is subtracted from each odd digit and three is added to each even digit in the number 94257636, how many digits will appear twice in the new number thus formed ?Options0231
Question
If two is subtracted from each odd digit and three is added to each even digit in the number 94257636, how many digits will appear twice in the new number thus formed ?Options0231
Solution
Sure, let's solve this step by step:
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First, identify the odd and even digits in the number 94257636. The odd digits are 9, 5, 7, 3 and the even digits are 4, 2, 6, 6.
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According to the problem, we need to subtract 2 from each odd digit and add 3 to each even digit. Doing this, we get:
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Subtracting 2 from each odd digit: 9-2=7, 5-2=3, 7-2=5, 3-2=1. So, the odd digits become 7, 3, 5, 1.
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Adding 3 to each even digit: 4+3=7, 2+3=5, 6+3=9, 6+3=9. So, the even digits become 7, 5, 9, 9.
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Now, combine these new digits to form the new number: 7357599.
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Finally, we need to find out how many digits appear twice in this new number. Looking at the number, we can see that the digits 7, 5, and 9 each appear twice.
So, the answer is 3. There are 3 digits that appear twice in the new number.
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