The vertex of a quadratic equation is given by the formula (-b/2a, f(-b/2a)) where a and b are coefficients from the quadratic equation in the form y = ax^2 + bx + c.

For the given equation y = x^2 + 3, the coefficients are a = 1, b = 0, and c = 3.

Step 1: Calculate -b/2a
-b/2a = -0/(2*1) = 0

Step 2: Substitute -b/2a into the equation to find the y-coordinate of the vertex
f(-b/2a) = (0)^2 + 3 = 3

So, the vertex of the quadratic y = x^2 + 3 is (0, 3).

Question

The vertex of a quadratic equation is given by the formula (-b/2a, f(-b/2a)) where a and b are coefficients from the quadratic equation in the form y = ax^2 + bx + c.

For the given equation y = x^2 + 3, the coefficients are a = 1, b = 0, and c = 3.

Step 1: Calculate -b/2a
-b/2a = -0/(2*1) = 0

Step 2: Substitute -b/2a into the equation to find the y-coordinate of the vertex
f(-b/2a) = (0)^2 + 3 = 3

So, the vertex of the quadratic y = x^2 + 3 is (0, 3).

Knowee AI · Accepted Answer

The vertex of a quadratic equation is given by the formula (-b/2a, f(-b/2a)) where a and b are coefficients from the quadratic equation in the form y = ax^2 + bx + c.

For the given equation y = x^2 + 3, the coefficients are a = 1, b = 0, and c = 3.

Step 1: Calculate -b/2a
-b/2a = -0/(2*1) = 0

Step 2: Substitute -b/2a into the equation to find the y-coordinate of the vertex
f(-b/2a) = (0)^2 + 3 = 3

So, the vertex of the quadratic y = x^2 + 3 is (0, 3).

find vertex of quadratic: y=x^2+3

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