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Two APs have the same common difference. The first term of one of these is 1- and that of the other is .8- Thenthe difference between their 4th terms is(a) 1- (b) 8-(c) 7 (d)

Question

Two APs have the same common difference. The first term of one of these is 1- and that of the other is .8- Thenthe difference between their 4th terms is(a) 1- (b) 8-(c) 7 (d)

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Solution

It seems like there's a mistake in your question as it's not clear. However, I'll try to answer based on the information given.

In an Arithmetic Progression (AP), the nth term is given by a + (n-1)d, where 'a' is the first term and 'd' is the common difference.

Given that the first term of the first AP is 1 and that of the second AP is 8, and both have the same common difference.

The 4th term of the first AP would be 1 + 3d and the 4th term of the second AP would be 8 + 3d.

The difference between their 4th terms would be (8 + 3d) - (1 + 3d) = 7.

So, the answer is (c) 7.

This problem has been solved

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