Convert the following Thevenin equivalent circuit into a Norton equivalent circuit if: V_th = 24V, R_th = 40.Question 13Answera.960.00A current source with a 40Ω and the R_load resistor in series.cross outb.0.60A current source with a series resistor of 40Ω, with the R-load resistor also connected in parallel.cross outc.0.60A current source with a parallel resistor of 40Ω, with the R-load resistor also connected in parallel.cross outd.960.00A current source with a parallel resistor of 40Ω, with the R-load resistor also connected in parallel.cross oute.0.60A current source with a 40Ω and R_load resistor in series.
Question
Convert the following Thevenin equivalent circuit into a Norton equivalent circuit if: V_th = 24V, R_th = 40.Question 13Answera.960.00A current source with a 40Ω and the R_load resistor in series.cross outb.0.60A current source with a series resistor of 40Ω, with the R-load resistor also connected in parallel.cross outc.0.60A current source with a parallel resistor of 40Ω, with the R-load resistor also connected in parallel.cross outd.960.00A current source with a parallel resistor of 40Ω, with the R-load resistor also connected in parallel.cross oute.0.60A current source with a 40Ω and R_load resistor in series.
Solution
The Norton equivalent circuit can be found by converting the Thevenin equivalent circuit. The Norton current (I_n) is the Thevenin voltage (V_th) divided by the Thevenin resistance (R_th), and the Norton resistance (R_n) is equal to the Thevenin resistance (R_th).
Given: V_th = 24V R_th = 40Ω
Step 1: Calculate the Norton current (I_n) I_n = V_th / R_th I_n = 24V / 40Ω I_n = 0.6A
Step 2: The Norton resistance (R_n) is equal to the Thevenin resistance (R_th) R_n = R_th R_n = 40Ω
So, the Norton equivalent circuit is a 0.6A current source with a parallel resistor of 40Ω, with the R-load resistor also connected in parallel. This corresponds to option c.
Similar Questions
Convert the following Norton equivalent circuit into a Thevenin equivalent circuit if: I_norton = 3A, R_norton = 14Ω.Question 14Answera.14.00V voltage source with a series resistor of 42.00Ω.cross outb.42.00V voltage source with a parallel resistor of 3Ω.cross outc.42.00V voltage source with a series resistor of 14Ω.cross outd.0.21V voltage source with a parallel resistor of 14Ω.cross oute.42.00V voltage source with a parallel resistor of 14Ω.
Thevenin’s equivalent circuit consists of______________and___________, in___________? If the load resistance is not given in the circuit.Short circuit voltage and load resistance, parallelOpen terminal voltage source and equivalent resistance across the terminal, seriesNone of the theseShort circuit terminal voltage and load resistance, series
Norton’s current is equal to ____________(0.5 نقطة)Open circuit currentShort circuit voltageOpen circuit voltageShort circuit current
. A Thevenin circuit is aresistor in series with a voltage sourceresistor in parallel with a voltage sourceresistor in series with a current source. resistor in parallel with a current source
A conductor of 2 ohms resistance in series is connected with a combination of two resistorsof 4 ohms each in parallel as shown in the figure.If the input provided by the battery is 24 volts, find:a. the equivalent resistance in the circuitb. the total current flowing in the circuitc. the potential difference across 4 ohms resistance
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