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Convert the following Norton equivalent circuit into a Thevenin equivalent circuit if:  I_norton = 3A, R_norton = 14Ω.Question 14Answera.14.00V voltage source with a series resistor of 42.00Ω.cross outb.42.00V voltage source with a parallel resistor of 3Ω.cross outc.42.00V voltage source with a series resistor of 14Ω.cross outd.0.21V voltage source with a parallel resistor of 14Ω.cross oute.42.00V voltage source with a parallel resistor of 14Ω.

Question

Convert the following Norton equivalent circuit into a Thevenin equivalent circuit if:  I_norton = 3A, R_norton = 14Ω.Question 14Answera.14.00V voltage source with a series resistor of 42.00Ω.cross outb.42.00V voltage source with a parallel resistor of 3Ω.cross outc.42.00V voltage source with a series resistor of 14Ω.cross outd.0.21V voltage source with a parallel resistor of 14Ω.cross oute.42.00V voltage source with a parallel resistor of 14Ω.

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Solution

The conversion from a Norton equivalent circuit to a Thevenin equivalent circuit is straightforward. The Thevenin resistance (R_thevenin) is equal to the Norton resistance (R_norton). Therefore, R_thevenin = R_norton = 14Ω.

The Thevenin voltage (V_thevenin) is the product of the Norton current (I_norton) and the Norton resistance (R_norton). Therefore, V_thevenin = I_norton * R_norton = 3A * 14Ω = 42V.

So, the Thevenin equivalent circuit is a 42.00V voltage source with a series resistor of 14.00Ω. This corresponds to option c.

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Similar Questions

Convert the following Thevenin equivalent circuit into a Norton equivalent circuit if:  V_th = 24V, R_th = 40.Question 13Answera.960.00A current source with a 40Ω and the R_load resistor in series.cross outb.0.60A current source with a series resistor of 40Ω, with the R-load resistor also connected in parallel.cross outc.0.60A current source with a parallel resistor of 40Ω, with the R-load resistor also connected in parallel.cross outd.960.00A current source with a parallel resistor of 40Ω, with the R-load resistor also connected in parallel.cross oute.0.60A current source with a 40Ω and R_load resistor in series.

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