f (x, y) = x2y + 7xy3 at (1, 2)
Question
f (x, y) = x2y + 7xy3 at (1, 2)
Solution
The function f(x, y) = x^2y + 7xy^3 at the point (1, 2) can be evaluated by substituting x = 1 and y = 2 into the function.
Step 1: Substitute x = 1 and y = 2 into the function
f(1, 2) = (1)^22 + 7(1)*(2)^3
Step 2: Simplify the expression
f(1, 2) = 2 + 7*8 = 2 + 56 = 58
So, f(1, 2) = 58.
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