If f(x,y)=x2 +y2, then fxy
Solution
The function given is f(x, y) = x^2 + y^2.
The partial derivative of f with respect to x is fx = 2x.
The partial derivative of f with respect to y is fy = 2y.
The second order mixed partial derivative fxy is the derivative of fx with respect to y.
Since fx = 2x is a constant with respect to y, its derivative with respect to y is 0.
So, fxy = 0.
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