Iodine reacts with ClO−3ClO3- under acidic conditions according to the reaction shown below.5 ClO−3+3 I2+3 H2O ⟶ 5 Cl−+6 IO−3+6 H+5 ClO3-+3 I2+3 H2O ⟶ 5 Cl-+6 IO3-+6 H+Does I2I2 act as the oxidizing agent or reducing agent in the reaction?A.Oxidizing agent, because I2I2 is reducedB.Reducing agent, because I2I2 is oxidizedC.Oxidizing agent, because ClO−3ClO3- is reducedD.Reducing agent, because ClO−3ClO3- is oxidized

b) Chlorine reacts with aqueous potassium iodide in a displacement reaction.Cl2 (aq) + 2I– (aq) 2Cl – (aq) + I2 (aq)(i) Explain, in terms of electrons, why chlorine is an oxidising agent in this reaction................................................................................................................................................................................................................................................................................. [1](ii) State the oxidation number of iodine in I2 .

In the reaction,  2Na2S2O3 + I2  =  Na2SO4 + 2NaI, I2  acts asSelect an answerAreducing agentBoxidizing agentCoxidizing as well as reducing agentDnone of the above

The chemical reaction between Hydrogen sulphide and iodine to give Hydrogen iodide and sulphur is given below:H2S + I2 → 2HI + S.The reducing and oxidising agents involved in this redox reaction are:Iodine and sulphur, respectivelyIodine and hydrogen sulphide, respectivelySulphur and iodine, respectivelyHydrogen sulphide and sulphur, respectively

Find out the process of oxidation, reduction oxidizing agent, reducing agent from thefollowing: -(a) MnO2 + 4HCl MnCl2 + 2H2O + Cl2(b) H2S + SO2  S + H2O(c) CuO + C  Cu + CO

Which element decreases its oxidation number in the following reaction?I + 2KCl 2KI + ClGroup of answer choicesiodineNo element decreases its oxidation number.chlorinepotassium