How many bytes will this statement allocate on a 64-bit machine?malloc(sizeof(char) * 10)40201080I don't know
Question
How many bytes will this statement allocate on a 64-bit machine?malloc(sizeof(char) * 10)40201080I don't know
Solution
The statement malloc(sizeof(char) * 10) will allocate 10 bytes on a 64-bit machine. Here's why:
sizeof(char)is always 1 byte by definition in C and C++.malloc(sizeof(char) * 10)is asking to allocate memory of size 10 times the size of a char. Since a char is 1 byte, this will allocate 10 bytes.
So, the answer is 10 bytes.
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To allocate enough space for an array of 10 integers (on a 64bit, Linux machine), I can use:malloc(64 * 10)malloc(10 * int)malloc(10 * sizeof(int))
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