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A 9:3:3:1 ratio is obtained in the F2 generation of a dihybrid cross when alleles assort from one another.

Question

A 9:3:3:1 ratio is obtained in the F2 generation of a dihybrid cross when alleles assort from one another.

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Solution

The 9:3:3:1 ratio is a classic Mendelian genetics ratio. It is observed in the F2 generation (second filial generation) of a dihybrid cross. Here's how it works:

  1. A dihybrid cross is a cross between two individuals that are both heterozygous for two traits. For example, an individual with genotype RrYy (where R and Y are dominant alleles and r and y are recessive alleles) is crossed with another individual with the same genotype (RrYy).

  2. In the F1 generation (first filial generation), all offspring will be heterozygous for both traits (RrYy) due to the dominance of the R and Y alleles.

  3. In the F2 generation, the alleles assort independently from one another. This means that the allele a parent passes on for one trait does not influence the allele passed on for the other trait.

  4. This independent assortment results in 16 possible combinations of alleles in the F2 generation.

  5. Out of these 16 combinations, 9 will have at least one dominant allele for both traits (RRYY, RRYy, RrYY, RrYy), 3 will have a dominant allele for the first trait and be homozygous recessive for the second trait (RRyy, Rryy), 3 will be homozygous recessive for the first trait and have a dominant allele for the second trait (rrYY, rrYy), and 1 will be homozygous recessive for both traits (rryy).

  6. This results in a phenotypic ratio of 9:3:3:1 in the F2 generation.

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