To calculate the energy lost by the roller coaster as it travels from the top to the bottom of the hill, we can use the principle of conservation of energy.

First, let's find the potential energy of the roller coaster at the top of the hill. The potential energy (PE) is given by the formula PE = mgh, where m is the mass of the roller coaster (400 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the hill (20 m).

PE = (400 kg)(9.8 m/s^2)(20 m) = 78,400 J

Next, let's find the kinetic energy of the roller coaster at the bottom of the hill. The kinetic energy (KE) is given by the formula KE = 0.5mv^2, where m is the mass of the roller coaster (400 kg) and v is the velocity of the roller coaster at the bottom of the hill (15 m/s).

KE = 0.5(400 kg)(15 m/s)^2 = 45,000 J

Finally, to find the energy lost by the roller coaster, we subtract the kinetic energy at the bottom of the hill from the potential energy at the top of the hill.

Energy lost = PE - KE = 78,400 J - 45,000 J = 33,400 J

Therefore, the roller coaster lost 33,400 J of energy when it traveled from the top to the bottom of the hill. The correct answer is d) 33,400 J.

Question

To calculate the energy lost by the roller coaster as it travels from the top to the bottom of the hill, we can use the principle of conservation of energy.

First, let's find the potential energy of the roller coaster at the top of the hill. The potential energy (PE) is given by the formula PE = mgh, where m is the mass of the roller coaster (400 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the hill (20 m).

PE = (400 kg)(9.8 m/s^2)(20 m) = 78,400 J

Next, let's find the kinetic energy of the roller coaster at the bottom of the hill. The kinetic energy (KE) is given by the formula KE = 0.5mv^2, where m is the mass of the roller coaster (400 kg) and v is the velocity of the roller coaster at the bottom of the hill (15 m/s).

KE = 0.5(400 kg)(15 m/s)^2 = 45,000 J

Finally, to find the energy lost by the roller coaster, we subtract the kinetic energy at the bottom of the hill from the potential energy at the top of the hill.

Energy lost = PE - KE = 78,400 J - 45,000 J = 33,400 J

Therefore, the roller coaster lost 33,400 J of energy when it traveled from the top to the bottom of the hill. The correct answer is d) 33,400 J.

Knowee AI · Accepted Answer

To calculate the energy lost by the roller coaster as it travels from the top to the bottom of the hill, we can use the principle of conservation of energy.

First, let's find the potential energy of the roller coaster at the top of the hill. The potential energy (PE) is given by the formula PE = mgh, where m is the mass of the roller coaster (400 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the hill (20 m).

PE = (400 kg)(9.8 m/s^2)(20 m) = 78,400 J

Next, let's find the kinetic energy of the roller coaster at the bottom of the hill. The kinetic energy (KE) is given by the formula KE = 0.5mv^2, where m is the mass of the roller coaster (400 kg) and v is the velocity of the roller coaster at the bottom of the hill (15 m/s).

KE = 0.5(400 kg)(15 m/s)^2 = 45,000 J

Finally, to find the energy lost by the roller coaster, we subtract the kinetic energy at the bottom of the hill from the potential energy at the top of the hill.

Energy lost = PE - KE = 78,400 J - 45,000 J = 33,400 J

Therefore, the roller coaster lost 33,400 J of energy when it traveled from the top to the bottom of the hill. The correct answer is d) 33,400 J.

A 400 kg roller coaster is stopped on top of a 20 m hill. It then races down the hill and at the bottom has a velocity of 15 m/s. How much energy did the roller coaster lose when it traveled from the top to the bottom of the hill? a78400 J b24800 J c45000 J d33400 J

Question

Solution

Similar Questions

Upgrade your grade with Knowee