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A 400 kg rollercoaster is on a 20 m hill and is not moving.  At the bottom of the hill, it has a velocity of 10 m/s. How much energy does the rollercoaster have at the bottom of the hill? a58400 J b78400 J c20000 J d98400 J

Question

A 400 kg rollercoaster is on a 20 m hill and is not moving.  At the bottom of the hill, it has a velocity of 10 m/s. How much energy does the rollercoaster have at the bottom of the hill? a58400 J b78400 J c20000 J d98400 J

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Solution

To solve this problem, we need to calculate the total energy of the rollercoaster at the bottom of the hill. This total energy is the sum of the kinetic energy and the potential energy.

  1. First, let's calculate the potential energy (PE) at the bottom of the hill. Since the rollercoaster is at the bottom, the height (h) is 0. The formula for potential energy is PE = mgh, where m is the mass and g is the acceleration due to gravity (9.8 m/s^2). So, PE = 400 kg * 9.8 m/s^2 * 0 = 0 J.

  2. Next, let's calculate the kinetic energy (KE) at the bottom of the hill. The formula for kinetic energy is KE = 1/2 * m * v^2, where m is the mass and v is the velocity. So, KE = 1/2 * 400 kg * (10 m/s)^2 = 20000 J.

  3. Finally, let's add the potential energy and the kinetic energy to get the total energy at the bottom of the hill: 0 J + 20000 J = 20000 J.

So, the answer is c) 20000 J.

This problem has been solved

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