This problem can be solved using Python programming language. Here is a simple Python program that checks if a number is an Armstrong number or not.

```python
# Function to check if a number is an Armstrong number
def is_armstrong(num):
# Initialize sum
sum = 0
# Find the sum of the cube of each digit
temp = num
while temp 0:
digit = temp % 10
sum += digit ** 3
temp //= 10
# If the sum is equal to the number, then it is an Armstrong number
if num == sum:
return True
else:
return False

# Input number
num = int(input("Enter a number: "))

# Check if the number is an Armstrong number
if is_armstrong(num):
print("Part of Memorable Coin")
else:
print("Not a Part of Memorable Coin")
```

This program works by taking an input number and checking if it is an Armstrong number. An Armstrong number is a number that is equal to the sum of the cubes of its digits. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153. The program uses a while loop to find the sum of the cubes of the digits of the number, and then checks if this sum is equal to the original number. If it is, the program prints "Part of Memorable Coin", otherwise it prints "Not a Part of Memorable Coin".

Question

This problem can be solved using Python programming language. Here is a simple Python program that checks if a number is an Armstrong number or not.

```python
# Function to check if a number is an Armstrong number
def is_armstrong(num):
    # Initialize sum
    sum = 0
    # Find the sum of the cube of each digit
    temp = num
    while temp > 0:
        digit = temp % 10
        sum += digit ** 3
        temp //= 10
    # If the sum is equal to the number, then it is an Armstrong number
    if num == sum:
        return True
    else:
        return False

# Input number
num = int(input("Enter a number: "))

# Check if the number is an Armstrong number
if is_armstrong(num):
    print("Part of Memorable Coin")
else:
    print("Not a Part of Memorable Coin")
```

This program works by taking an input number and checking if it is an Armstrong number. An Armstrong number is a number that is equal to the sum of the cubes of its digits. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153. The program uses a while loop to find the sum of the cubes of the digits of the number, and then checks if this sum is equal to the original number. If it is, the program prints "Part of Memorable Coin", otherwise it prints "Not a Part of Memorable Coin".

Knowee AI · Accepted Answer

This problem can be solved using Python programming language. Here is a simple Python program that checks if a number is an Armstrong number or not.

```python
# Function to check if a number is an Armstrong number
def is_armstrong(num):
    # Initialize sum
    sum = 0
    # Find the sum of the cube of each digit
    temp = num
    while temp > 0:
        digit = temp % 10
        sum += digit ** 3
        temp //= 10
    # If the sum is equal to the number, then it is an Armstrong number
    if num == sum:
        return True
    else:
        return False

# Input number
num = int(input("Enter a number: "))

# Check if the number is an Armstrong number
if is_armstrong(num):
    print("Part of Memorable Coin")
else:
    print("Not a Part of Memorable Coin")
```

This program works by taking an input number and checking if it is an Armstrong number. An Armstrong number is a number that is equal to the sum of the cubes of its digits. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153. The program uses a while loop to find the sum of the cubes of the digits of the number, and then checks if this sum is equal to the original number. If it is, the program prints "Part of Memorable Coin", otherwise it prints "Not a Part of Memorable Coin".

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