What is the perimeter of a rectangular room that has a length of 9.9 m and a width that is 2 m less than the length? (Answer correct to one decimal place.)
Question
What is the perimeter of a rectangular room that has a length of 9.9 m and a width that is 2 m less than the length? (Answer correct to one decimal place.)
Solution
To find the perimeter of a rectangle, you use the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
Step 1: Identify the length and width of the rectangle. The length is given as 9.9 m. The width is 2 m less than the length, so it is 9.9 m - 2 m = 7.9 m.
Step 2: Substitute the length and width into the formula. P = 2(9.9 m + 7.9 m).
Step 3: Add the length and width. 9.9 m + 7.9 m = 17.8 m.
Step 4: Multiply the result by 2. P = 2 * 17.8 m = 35.6 m.
So, the perimeter of the rectangular room is 35.6 m.
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