Next, find Q1.Recall that the first quartile, Q1, is the median of the lower half of the data. That is, the median of the data located below the Q2 position.Consider the ordered list of data values. The median, Q2, which was determined in the last step, has been underlined for clarity.3,   6,   6,   7,   8,   8,   9,   10,   11There are nine values in the whole data set, but there are only values to the left of the underlined median. The first quartile, Q1, will be equal to the median of these values.Since the lower half of the data has an even number of data values, we will now use the rule to find the median of an even number of data values.median = sum of middle two values2The middle two values of the lower half of the data set are 6 and .Now, calculate the first quartile. Q1.Q1  =  6 + 2  =  2  =

It seems like there is a mistake in the text you provided. The middle two values of the lower half of the data set are not clearly mentioned. However, I can explain how to find Q1 in general.

1. First, you need to sort the data in ascending order, which has already been done in your case.

2. Then, find the median (Q2). If the number of data points is odd, the median is the middle number. If the number of data points is even, the median is the average of the two middle numbers. In your case, the median (Q2) is 8.

3. To find Q1, you need to consider only the lower half of the data, i.e., the data points to the left of the median. In your case, these are 3, 6, 6, 7.

4. If the lower half has an odd number of data points, Q1 is the middle number. If it has an even number of data points, Q1 is the average of the two middle numbers. In your case, the lower half has an even number of data points, so Q1 would be the average of 6 and 6, which is 6.

So, Q1 in your data set should be 6.