The elastic potential energy stored in a spring can be calculated using the formula:

PE = 0.5 * k * x^2

where:
PE is the elastic potential energy,
k is the spring constant, and
x is the displacement from the equilibrium position.

Given in the problem, k = 423 N/m and x = 4.51 cm = 0.0451 m (since 1 cm = 0.01 m).

Substituting these values into the formula, we get:

PE = 0.5 * 423 N/m * (0.0451 m)^2

Now, calculate the value inside the parentheses first:

(0.0451 m)^2 = 0.00203521 m^2

Then, multiply this by the spring constant and 0.5:

PE = 0.5 * 423 N/m * 0.00203521 m^2 = 0.430 N*m = 0.430 Joules

So, the amount of elastic potential energy stored in the spring is approximately 0.430 Joules.

Question

The elastic potential energy stored in a spring can be calculated using the formula:

PE = 0.5 * k * x^2

where:
PE is the elastic potential energy,
k is the spring constant, and
x is the displacement from the equilibrium position.

Given in the problem, k = 423 N/m and x = 4.51 cm = 0.0451 m (since 1 cm = 0.01 m).

Substituting these values into the formula, we get:

PE = 0.5 * 423 N/m * (0.0451 m)^2

Now, calculate the value inside the parentheses first:

(0.0451 m)^2 = 0.00203521 m^2

Then, multiply this by the spring constant and 0.5:

PE = 0.5 * 423 N/m * 0.00203521 m^2 = 0.430 N*m = 0.430 Joules

So, the amount of elastic potential energy stored in the spring is approximately 0.430 Joules.

Knowee AI · Accepted Answer