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Prince stretched a circular spring with a spring constant of 3 N/m until it was extended to 50cm. What is the elastic potential energy of the spring stretched by Prince/ stored by the spring?2. How much elastic potential energy does a spring store when it is compressed by 0.2 m if ithas a spring constant of 5 N/m?3. What is the elastic potential energy stored in a spring whose spring constant is 160 N/m when itis 8.0 cm compressed?

Question

Prince stretched a circular spring with a spring constant of 3 N/m until it was extended to 50cm. What is the elastic potential energy of the spring stretched by Prince/ stored by the spring?2. How much elastic potential energy does a spring store when it is compressed by 0.2 m if ithas a spring constant of 5 N/m?3. What is the elastic potential energy stored in a spring whose spring constant is 160 N/m when itis 8.0 cm compressed?

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Solution

  1. The elastic potential energy (PE) of a spring can be calculated using the formula PE = 0.5 * k * x^2, where k is the spring constant and x is the displacement (extension or compression) of the spring from its equilibrium position.

For the first spring:

  • The spring constant, k = 3 N/m
  • The extension, x = 50 cm = 0.5 m (since 1m = 100cm)

Substituting these values into the formula, we get:

PE = 0.5 * 3 N/m * (0.5 m)^2 = 0.375 Joules

  1. For the second spring:
  • The spring constant, k = 5 N/m
  • The compression, x = 0.2 m

Substituting these values into the formula, we get:

PE = 0.5 * 5 N/m * (0.2 m)^2 = 0.1 Joules

  1. For the third spring:
  • The spring constant, k = 160 N/m
  • The compression, x = 8.0 cm = 0.08 m (since 1m = 100cm)

Substituting these values into the formula, we get:

PE = 0.5 * 160 N/m * (0.08 m)^2 = 0.512 Joules

So, the elastic potential energy stored in the first, second, and third springs are 0.375 Joules, 0.1 Joules, and 0.512 Joules respectively.

This problem has been solved

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