To find the volume flow rate, we can use the formula for the flow rate of a fluid which is Q = A * v, where A is the cross-sectional area of the pipe (or in this case, the needle) and v is the velocity of the fluid (or in this case, the air).

First, we need to convert the radius from millimeters to feet because the velocity is given in feet per second. There are approximately 0.00328084 feet in a millimeter, so the radius in feet is 4.5 mm * 0.00328084 ft/mm = 0.0147638 ft.

The cross-sectional area A of the needle can be found using the formula for the area of a circle, which is A = πr^2. Substituting the radius we found, we get A = π * (0.0147638 ft)^2 = 0.000683 ft^2.

Now we can find the volume flow rate Q by multiplying the area A by the velocity v: Q = A * v = 0.000683 ft^2 * 8.2 ft/s = 0.0056 ft^3/s.

Finally, we need to convert this volume flow rate from cubic feet per second to cubic centimeters per second. There are approximately 28316.8 cubic centimeters in a cubic foot, so Q = 0.0056 ft^3/s * 28316.8 cm^3/ft^3 = 158.57 cm^3/s.

So, the volume flow rate of the air being pumped into the football is approximately 159 cm^3/s.

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To find the volume flow rate, we can use the formula for the flow rate of a fluid which is Q = A * v, where A is the cross-sectional area of the pipe (or in this case, the needle) and v is the velocity of the fluid (or in this case, the air).

First, we need to convert the radius from millimeters to feet because the velocity is given in feet per second. There are approximately 0.00328084 feet in a millimeter, so the radius in feet is 4.5 mm * 0.00328084 ft/mm = 0.0147638 ft.

The cross-sectional area A of the needle can be found using the formula for the area of a circle, which is A = πr^2. Substituting the radius we found, we get A = π * (0.0147638 ft)^2 = 0.000683 ft^2.

Now we can find the volume flow rate Q by multiplying the area A by the velocity v: Q = A * v = 0.000683 ft^2 * 8.2 ft/s = 0.0056 ft^3/s.

Finally, we need to convert this volume flow rate from cubic feet per second to cubic centimeters per second. There are approximately 28316.8 cubic centimeters in a cubic foot, so Q = 0.0056 ft^3/s * 28316.8 cm^3/ft^3 = 158.57 cm^3/s.

So, the volume flow rate of the air being pumped into the football is approximately 159 cm^3/s.

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To find the volume flow rate, we can use the formula for the flow rate of a fluid which is Q = A * v, where A is the cross-sectional area of the pipe (or in this case, the needle) and v is the velocity of the fluid (or in this case, the air).

First, we need to convert the radius from millimeters to feet because the velocity is given in feet per second. There are approximately 0.00328084 feet in a millimeter, so the radius in feet is 4.5 mm * 0.00328084 ft/mm = 0.0147638 ft.

The cross-sectional area A of the needle can be found using the formula for the area of a circle, which is A = πr^2. Substituting the radius we found, we get A = π * (0.0147638 ft)^2 = 0.000683 ft^2.

Now we can find the volume flow rate Q by multiplying the area A by the velocity v: Q = A * v = 0.000683 ft^2 * 8.2 ft/s = 0.0056 ft^3/s.

Finally, we need to convert this volume flow rate from cubic feet per second to cubic centimeters per second. There are approximately 28316.8 cubic centimeters in a cubic foot, so Q = 0.0056 ft^3/s * 28316.8 cm^3/ft^3 = 158.57 cm^3/s.

So, the volume flow rate of the air being pumped into the football is approximately 159 cm^3/s.

You need to fill a football with air to play with it. You know that your pump expels air at speed of 8.2 ft/s. The needle of your pump has a radius of 4.5 millimeters. What is the volume flow rate of the air being pumped into the football?1 point159 cm^3 / s276 cm^3/s51 cm^3/s634 cm^3/s

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