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A container holds 60.0 mL of nitrogen at 30.0 degrees Celsius. What will be its volume if the temperature increases to 65.0 degrees Celsius?

Question

A container holds 60.0 mL of nitrogen at 30.0 degrees Celsius. What will be its volume if the temperature increases to 65.0 degrees Celsius?

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Solution

This problem can be solved using Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas are kept constant. The formula for Charles's Law is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Here are the steps to solve the problem:

  1. Convert the initial and final temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 30.0°C + 273.15 = 303.15 K and T2 = 65.0°C + 273.15 = 338.15 K.

  2. Substitute the known values into Charles's Law formula. So, (60.0 mL / 303.15 K) = V2 / 338.15 K.

  3. Solve for V2 by multiplying both sides of the equation by 338.15 K. So, V2 = (60.0 mL / 303.15 K) * 338.15 K.

  4. Calculate V2 to find the final volume. V2 ≈ 67.0 mL.

So, if the temperature of the nitrogen increases from 30.0 degrees Celsius to 65.0 degrees Celsius, the volume of the nitrogen will increase to approximately 67.0 mL.

This problem has been solved

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