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What will be the result of following Python code snippet after execution?str1=""i=0var2=1while(i<3): var1=1 if str1: var2=var1*var2+5 else: var2=var1*var2+1 i=i+1print(var2)1612114

Question

What will be the result of following Python code snippet after execution?str1=""i=0var2=1while(i<3): var1=1 if str1: var2=var1var2+5 else: var2=var1var2+1 i=i+1print(var2)1612114

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Solution

The provided Python code snippet is not correctly formatted, which makes it difficult to predict the output. However, I'll try to interpret it as best as I can.

str1=""
i=0
var2=1
while(i<3):
    var1=1
    if str1:
        var2=var1*var2+5
    else:
        var2=var1*var2+1
    i=i+1
print(var2)

In this code, str1 is an empty string, i is initialized to 0, and var2 is initialized to 1. The while loop will run as long as i is less than 3.

Inside the loop, var1 is set to 1. Then, there's an if-else statement that checks if str1 is truthy. In Python, an empty string is considered falsy, so the else branch will be executed. This will set var2 to var1*var2+1, which is 1*1+1 = 2 in the first iteration.

i is then incremented by 1, and the loop continues. In the second iteration, var2 will be 1*2+1 = 3, and in the third iteration, var2 will be 1*3+1 = 4.

After the loop has run three times, i will be 3, so the loop will stop. The final value of var2, which is 4, will be printed.

So, the output of this code should be 4.

This problem has been solved

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