1. Write a C program that takes n number of positive integers. Find the integer that appears the least number of times among the said integers. If there are multiple such integers, select the smallest one
Question
- Write a C program that takes n number of positive integers. Find the integer that appears the least number of times among the said integers. If there are multiple such integers, select the smallest one
Solution
Sure, here is a simple C program that fulfills your requirements:
#include <stdio.h>
#include <limits.h>
#define MAX 100
int main() {
int arr[MAX], freq[MAX];
int size, i, j, count;
printf("Enter size of array: ");
scanf("%d", &size);
printf("Enter elements in array: ");
for(i=0; i<size; i++) {
scanf("%d", &arr[i]);
freq[i] = -1;
}
for(i=0; i<size; i++) {
count = 1;
for(j=i+1; j<size; j++) {
if(arr[i]==arr[j]) {
count++;
freq[j] = 0;
}
}
if(freq[i] != 0) {
freq[i] = count;
}
}
int minCount = INT_MAX;
int num = 0;
for(i=0; i<size; i++) {
if(freq[i] != 0 && freq[i] < minCount) {
minCount = freq[i];
num = arr[i];
} else if(freq[i] == minCount && arr[i] < num) {
num = arr[i];
}
}
printf("The number with minimum frequency and smallest in case of a tie is: %d\n", num);
return 0;
}
This program works by first taking the size of the array as input, then the elements of the array. It maintains a frequency array to keep track of the frequency of each element. It then iterates over the array to find the element with the minimum frequency. If there is a tie, it selects the smallest element.
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