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The specific heat of copper is 0.385 J/(g ∙ °C). If 34.2 g of copper, initially at 25°C, absorbs 4.689 kJ, what will be the final temperature of the copper?Group of answer choices125 °C266 °C300 °C381 °C

Question

The specific heat of copper is 0.385 J/(g ∙ °C). If 34.2 g of copper, initially at 25°C, absorbs 4.689 kJ, what will be the final temperature of the copper?Group of answer choices125 °C266 °C300 °C381 °C

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Solution

To solve this problem, we need to use the formula for heat transfer:

q = mcΔT

where: q = heat absorbed or released (in Joules) m = mass (in grams) c = specific heat capacity (in J/g°C) ΔT = change in temperature (in °C)

We know that: q = 4.689 kJ = 4689 J (since 1 kJ = 1000 J) m = 34.2 g c = 0.385 J/g°C

We want to find ΔT, which is (T_final - T_initial). We know that T_initial = 25°C.

Substituting the known values into the formula, we get:

4689 J = 34.2 g * 0.385 J/g°C * ΔT

Solving for ΔT, we get:

ΔT = 4689 J / (34.2 g * 0.385 J/g°C) = 353.5°C

So, the final temperature T_final = T_initial + ΔT = 25°C + 353.5°C = 378.5°C

The closest answer to this is 381°C.

This problem has been solved

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