A constant retarding force of 50 N is supplied to a body of 70 kgmoving initially with a speed of 15 m/s . How long does the bodytake to stop ?
Question
A constant retarding force of 50 N is supplied to a body of 70 kgmoving initially with a speed of 15 m/s . How long does the bodytake to stop ?
Solution
Sure, let's solve this step by step:
Step 1: Identify the given values.
- Force (F) = -50 N (It's negative because it's a retarding force)
- Mass (m) = 70 kg
- Initial speed (u) = 15 m/s
- Final speed (v) = 0 m/s (The body stops)
Step 2: Use Newton's second law of motion to find the acceleration. Newton's second law states that Force = mass * acceleration, or F = ma. So, acceleration (a) = F/m = -50 N / 70 kg = -0.714 m/s²
Step 3: Use the first equation of motion to find the time. The first equation of motion is v = u + at. Rearranging for time, we get t = (v - u) / a = (0 - 15 m/s) / -0.714 m/s² = 21 seconds.
So, the body takes 21 seconds to stop.
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