To solve this problem, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas remain constant. The formula is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Step 1: Convert the temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 10.0°C + 273.15 = 283.15 K and T2 = 30.0°C + 273.15 = 303.15 K.

Step 2: Substitute the known values into the formula. We know V1 = 10.0 mL, T1 = 283.15 K, and T2 = 303.15 K, and we're solving for V2. So, (10.0 mL / 283.15 K) = V2 / 303.15 K.

Step 3: Solve for V2. Cross-multiplying gives us V2 = (10.0 mL / 283.15 K) * 303.15 K = 10.7 mL.

So, the new volume of the ball when the temperature is raised to 30.0°C is 10.7 mL.

Question

To solve this problem, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas remain constant. The formula is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Step 1: Convert the temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 10.0°C + 273.15 = 283.15 K and T2 = 30.0°C + 273.15 = 303.15 K.

Step 2: Substitute the known values into the formula. We know V1 = 10.0 mL, T1 = 283.15 K, and T2 = 303.15 K, and we're solving for V2. So, (10.0 mL / 283.15 K) = V2 / 303.15 K.

Step 3: Solve for V2. Cross-multiplying gives us V2 = (10.0 mL / 283.15 K) * 303.15 K = 10.7 mL.

So, the new volume of the ball when the temperature is raised to 30.0°C is 10.7 mL.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas remain constant. The formula is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Step 1: Convert the temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 10.0°C + 273.15 = 283.15 K and T2 = 30.0°C + 273.15 = 303.15 K.

Step 2: Substitute the known values into the formula. We know V1 = 10.0 mL, T1 = 283.15 K, and T2 = 303.15 K, and we're solving for V2. So, (10.0 mL / 283.15 K) = V2 / 303.15 K.

Step 3: Solve for V2. Cross-multiplying gives us V2 = (10.0 mL / 283.15 K) * 303.15 K = 10.7 mL.

So, the new volume of the ball when the temperature is raised to 30.0°C is 10.7 mL.

An inflatable ball has a volume of 10.0 mL at a temperature of 10.0°C. If the temperature is raised to 30.0°C at constant pressure, what is the new volume of the ball?Multiple choice question.9.34 mL10.7 mL3.33 mL30.0 mL

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