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Write a Verilog code to implement the Boolean Expression Y = (A+B)'. Write the correspondingTestbench code for the verification of your Verilog code. Identify the gate that matches to thisoperation.

Question

Write a Verilog code to implement the Boolean Expression Y = (A+B)'. Write the correspondingTestbench code for the verification of your Verilog code. Identify the gate that matches to thisoperation.

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Solution

Sure, here is the Verilog code for the Boolean expression Y = (A+B)'.

module top_module (input A, B, output Y);
  assign Y = ~(A | B);
endmodule

The gate that matches this operation is the NOR gate.

Now, let's write the corresponding testbench code for the verification of the Verilog code.

module testbench;
  reg A, B;
  wire Y;

  top_module u1 (.A(A), .B(B), .Y(Y));

  initial begin
    A = 0; B = 0; #10;
    A = 0; B = 1; #10;
    A = 1; B = 0; #10;
    A = 1; B = 1; #10;
  end

  initial begin
    $monitor("At time %d, A = %b, B = %b, Y = %b", $time, A, B, Y);
  end
endmodule

This testbench will test all possible combinations of inputs A and B and print the output Y at each step.

This problem has been solved

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