The reaction between methane (CH4) and chlorine (Cl2) is a substitution reaction, specifically a radical halogenation. This reaction occurs in the presence of UV light or heat. The chlorine replaces one of the hydrogen atoms in the methane molecule.

Here are the steps:

1. Initiation: The chlorine molecules absorb UV light and undergo homolytic fission to form two chlorine radicals. This is the initiation step that starts the chain reaction.

2. Propagation: The chlorine radical collides with a methane molecule and takes away one hydrogen to form hydrogen chloride (HCl) and a methyl radical (CH3). The methyl radical can then react with another chlorine molecule to form chloromethane (CH3Cl) and another chlorine radical. This chlorine radical can then react with another methane molecule, and the cycle continues.

3. Termination: The reaction stops when two radicals collide to form a molecule. For example, two methyl radicals could combine to form ethane, or a methyl radical and a chlorine radical could combine to form more chloromethane.

So, the possible products of the reaction are CH3Cl and HCl.

Question

The reaction between methane (CH4) and chlorine (Cl2) is a substitution reaction, specifically a radical halogenation. This reaction occurs in the presence of UV light or heat. The chlorine replaces one of the hydrogen atoms in the methane molecule.

Here are the steps:

1. Initiation: The chlorine molecules absorb UV light and undergo homolytic fission to form two chlorine radicals. This is the initiation step that starts the chain reaction.

2. Propagation: The chlorine radical collides with a methane molecule and takes away one hydrogen to form hydrogen chloride (HCl) and a methyl radical (CH3). The methyl radical can then react with another chlorine molecule to form chloromethane (CH3Cl) and another chlorine radical. This chlorine radical can then react with another methane molecule, and the cycle continues.

3. Termination: The reaction stops when two radicals collide to form a molecule. For example, two methyl radicals could combine to form ethane, or a methyl radical and a chlorine radical could combine to form more chloromethane.

So, the possible products of the reaction are CH3Cl and HCl.

Knowee AI · Accepted Answer

The reaction between methane (CH4) and chlorine (Cl2) is a substitution reaction, specifically a radical halogenation. This reaction occurs in the presence of UV light or heat. The chlorine replaces one of the hydrogen atoms in the methane molecule.

Here are the steps:

1. Initiation: The chlorine molecules absorb UV light and undergo homolytic fission to form two chlorine radicals. This is the initiation step that starts the chain reaction.

2. Propagation: The chlorine radical collides with a methane molecule and takes away one hydrogen to form hydrogen chloride (HCl) and a methyl radical (CH3). The methyl radical can then react with another chlorine molecule to form chloromethane (CH3Cl) and another chlorine radical. This chlorine radical can then react with another methane molecule, and the cycle continues.

3. Termination: The reaction stops when two radicals collide to form a molecule. For example, two methyl radicals could combine to form ethane, or a methyl radical and a chlorine radical could combine to form more chloromethane.

So, the possible products of the reaction are CH3Cl and HCl.

CH4 + Cl2 --> Predict possible products for above reactionGroup of answer choicesCH3ClCCl4CH3Cl + HClCH2Cl2

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